The math challenge.

[Capm]

Here are the rules:
Starting with a simple equation, each next one must become progressively more difficult.
Each equation must begin with the answer to the previous.
No answer may come out as 0.
No answer may come out as Infinity.
Altho both may be a "part" of the answer.
See how far it goes.

To keep things neat, put the answer to the previous in quotes (or code) brackets.

Soooo, to start things off:

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2

2+2=

[Admiral Thrawn]

4-2 =

[fyrephlie]

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2

2 x 4 =

[DCrazy]

8^2=

[fyrephlie]

to keep things moving...

To keep things neat, put the answer to the previous in quotes (or code) brackets.

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64

where x=2

64(x^3) =

[Nirvana]

Next is the English "challange"!

[Capm]

Silence you!

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512

(where y=2)

512/y(41^4+371)

[fyrephlie]

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723,489,792

a = 1
b = 2
c = 3
d = 5
e = 8
f = 13
g = 21
(fibonnacci continues through z by adding the previous two numbers to make the next variable)

solve (z(q/x)(g-f))^2

(that ought to keep you busy for a while):P

[Capm]

fyrephlie your last answer was incorrect and your next equation doesn't conform to the rules.

Here I'll change the variable letter to make it less confusing

[Krom]

You may want to rethink how you wrote that equation capm. Firefly simply stuck it into google and got that answer. Google calculates it as:

(512 / 2) * ((41^4) + 371) = 723,489,792

Were you intending on calculating it as 512 / (2(41^4)+371))? (9.0583171628218356396658047111741e-5)

[Capm]

Doh, you are right! I forgot a *couple* pairs of thingymajoodles.




(where y=2)

512/(y((41^4)+371))

[Vertigo 99]

[Capm]

Oh come on, Lothar and Drakona haven't even hit the thread yet!

[Krom]

Being slightly proficient with a calculator does not make you a nerd, posting forum macros does.

[fyrephlie]

fyrephlie your last answer was incorrect and your next equation doesn't conform to the rules.

Here I'll change the variable letter to make it less confusing

my answer was right the way you wrote it... (per KCalc:))

and the next was supposed to be

723,489,792 - (z(q/x)(g-f))^2

[Vertigo 99]

Being slightly proficient with a calculator does not make you a nerd, posting forum macros does.

this post would have merit if there was any possible way i could believe you were being serious

[fyrephlie]

ok ... the fact that this is the DESCENT BULLETIN BOARD inherantly makes us all nerds... now someone answer my 'problem' so we can move on.

[Drakona]

fyrephlie -

723,489,792 - (z(q/x)(g-f))^2

723,489,792 - [ (196418) * (2584 / 75025) * (21 - 13) ]^2

723,489,792 - ( 4060352896 / 75025 )^2

(4072343618901120000 - 16486546847213506816) / 5628750625

-12414203228312386816 / 5628750625

I printed it like that for one reason and one reason only. That fraction is in lowest terms. Honest. I checked (the bottom prime factors easily). Holy schlamoly.

Couldn't have been bothered to make it come out an integer, could we? Jolly good friends with the rationals, now are we?

Right back atcha.

-(12414203228312386816 / 5628750625) * (2543972374969249 / 48492981360595261) *
(232058125/26849557152500992)

[DCrazy]

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-1e18

(n = -1e18)

nx^3 - 2nx^2 + 3nx + 4n = 0

Solve for x.

[Flabby Chick]

I got lost at this point........

2+2=

[Lothar]

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-1e18

Check that again.

The numerators have a combined 45 digits. The denominators have a combined 44 digits. This means your answer's magnitude should be within a couple orders of magnitude of 10 -- somewhere between .1 and 1000.

1,000,000,000,000,000,000 is not within this range.

[DCrazy]

Farking Google calculator. Since it didn't like the equation as it stood, I did it piecewise and used Notepad for scratch... when I copied/pasted I must have kept 1042 instead of making it 42.

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-1

-x^3 + 2x^2 - 3nx + 4n = 0

Solve for x.